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Divides the first value by the second, returning 0 for division by 0 for each matched pair of bands in image1 and image2. If either image1 or image2 has only 1 band, then it is used against all the bands in the other image. If the images have the same number of bands, but not the same names, they're used pairwise in the natural order. The output bands are named for the longer of the two inputs, or if they're equal in length, in image1's order. The type of the output pixels is the union of the input types.
Usage
Returns
Image.divide(image2)
Image
Argument
Type
Details
this:image1
Image
The image from which the left operand bands are taken.
image2
Image
The image from which the right operand bands are taken.
[[["Easy to understand","easyToUnderstand","thumb-up"],["Solved my problem","solvedMyProblem","thumb-up"],["Other","otherUp","thumb-up"]],[["Missing the information I need","missingTheInformationINeed","thumb-down"],["Too complicated / too many steps","tooComplicatedTooManySteps","thumb-down"],["Out of date","outOfDate","thumb-down"],["Samples / code issue","samplesCodeIssue","thumb-down"],["Other","otherDown","thumb-down"]],["Last updated 2023-10-06 UTC."],[[["\u003cp\u003e\u003ccode\u003eimage1.divide(image2)\u003c/code\u003e performs element-wise division between matching bands of two images, returning 0 for divisions by 0.\u003c/p\u003e\n"],["\u003cp\u003eIf the input images have different numbers of bands, single-band images are applied to all bands of the other image, and if they have the same number of bands but different names, bands are paired in their natural order.\u003c/p\u003e\n"],["\u003cp\u003eThe output image's band names and type are determined by the longer input image or, if equal in length, by \u003ccode\u003eimage1\u003c/code\u003e's properties.\u003c/p\u003e\n"],["\u003cp\u003eThe output pixel type is derived from the union of the input pixel types, accommodating potential differences in data representation.\u003c/p\u003e\n"]]],[],null,["# ee.Image.divide\n\nDivides the first value by the second, returning 0 for division by 0 for each matched pair of bands in image1 and image2. If either image1 or image2 has only 1 band, then it is used against all the bands in the other image. If the images have the same number of bands, but not the same names, they're used pairwise in the natural order. The output bands are named for the longer of the two inputs, or if they're equal in length, in image1's order. The type of the output pixels is the union of the input types.\n\n\u003cbr /\u003e\n\n| Usage | Returns |\n|------------------------|---------|\n| Image.divide`(image2)` | Image |\n\n| Argument | Type | Details |\n|----------------|-------|---------------------------------------------------------|\n| this: `image1` | Image | The image from which the left operand bands are taken. |\n| `image2` | Image | The image from which the right operand bands are taken. |\n\nExamples\n--------\n\n### Code Editor (JavaScript)\n\n```javascript\n// A Sentinel-2 surface reflectance image.\nvar img = ee.Image('COPERNICUS/S2_SR/20210109T185751_20210109T185931_T10SEG');\n\n// Subset two image bands and display them on the map.\nvar swir1 = img.select('B11');\nvar swir2 = img.select('B12');\nMap.setCenter(-122.276, 37.456, 12);\nMap.addLayer(swir1, {min: 0, max: 3000}, 'swir1');\nMap.addLayer(swir2, {min: 0, max: 3000}, 'swir2');\n\n// The following examples demonstrate ee.Image arithmetic methods using two\n// single-band ee.Image inputs.\nvar addition = swir1.add(swir2);\nMap.addLayer(addition, {min: 100, max: 6000}, 'addition');\n\nvar subtraction = swir1.subtract(swir2);\nMap.addLayer(subtraction, {min: 0, max: 1500}, 'subtraction');\n\nvar multiplication = swir1.multiply(swir2);\nMap.addLayer(multiplication, {min: 1.9e5, max: 9.4e6}, 'multiplication');\n\nvar division = swir1.divide(swir2);\nMap.addLayer(division, {min: 0, max: 3}, 'division');\n\nvar remainder = swir1.mod(swir2);\nMap.addLayer(remainder, {min: 0, max: 1500}, 'remainder');\n\n// If a number input is provided as the second argument, it will automatically\n// be promoted to an ee.Image object, a convenient shorthand for constants.\nvar exponent = swir1.pow(3);\nMap.addLayer(exponent, {min: 0, max: 2e10}, 'exponent');\n```\nPython setup\n\nSee the [Python Environment](/earth-engine/guides/python_install) page for information on the Python API and using\n`geemap` for interactive development. \n\n```python\nimport ee\nimport geemap.core as geemap\n```\n\n### Colab (Python)\n\n```python\n# A Sentinel-2 surface reflectance image.\nimg = ee.Image('COPERNICUS/S2_SR/20210109T185751_20210109T185931_T10SEG')\n\n# Subset two image bands and display them on the map.\nswir_1 = img.select('B11')\nswir_2 = img.select('B12')\nm = geemap.Map()\nm.set_center(-122.276, 37.456, 12)\nm.add_layer(swir_1, {'min': 0, 'max': 3000}, 'swir_1')\nm.add_layer(swir_2, {'min': 0, 'max': 3000}, 'swir_2')\n\n# The following examples demonstrate ee.Image arithmetic methods using two\n# single-band ee.Image inputs.\naddition = swir_1.add(swir_2)\nm.add_layer(addition, {'min': 100, 'max': 6000}, 'addition')\n\nsubtraction = swir_1.subtract(swir_2)\nm.add_layer(subtraction, {'min': 0, 'max': 1500}, 'subtraction')\n\nmultiplication = swir_1.multiply(swir_2)\nm.add_layer(multiplication, {'min': 1.9e5, 'max': 9.4e6}, 'multiplication')\n\ndivision = swir_1.divide(swir_2)\nm.add_layer(division, {'min': 0, 'max': 3}, 'division')\n\nremainder = swir_1.mod(swir_2)\nm.add_layer(remainder, {'min': 0, 'max': 1500}, 'remainder')\n\n# If a number input is provided as the second argument, it will automatically\n# be promoted to an ee.Image object, a convenient shorthand for constants.\nexponent = swir_1.pow(3)\nm.add_layer(exponent, {'min': 0, 'max': 2e10}, 'exponent')\nm\n```"]]
