{\bf Fundamental open problem}: Give the definition of the division by zero calculus for multiply-valued functions with singularities, \medskip In order to make clear the problem, we shall give a prototype example. We have the identity by the divison by zero calculus: \begin{equation} f(z) = \frac{1 + z}{1- z} =-1 , \quad \text{at} \quad z = 1. \end{equation} By the real part and imaginary part of the function, we have for $ z= x +iy$ \begin{equation} \frac{1 - x^2 - y^2}{(1 - x)^2 + y^2} =-1, \quad \text{at}\quad (1,0) \end{equation} and \begin{equation} \frac{y}{(1- x)^2 + y^2} = 0, \quad \text{at}\quad (1,0), \end{equation} respectively. Why the differences happen? In general, we are interested in the above open question. Recall our definition for the division by zero calculus. The division by zero is uniquely and reasonably determined as 1/0=0/0=z/0=0 in the natural extensions of fractions. We have to change our basic ideas for our space and world: Division by Zero z/0 = 0 in Euclidean Spaces Hiroshi Michiwaki, Hiroshi Okumura and Saburou Saitoh International Journal of Mathematics and Computation Vol. 28(2017); Issue 1, 2017), 1-16. http://www.scirp.org/journal/alamt http://dx.doi.org/10.4236/alamt.2016.62007 http://www.ijapm.org/show-63-504-1.html http://www.diogenes.bg/ijam/contents/2014-27-2/9/9.pdf http://okmr.yamatoblog.net/…/announcement%20326-%20the%20di… Announcement 326: The division by zero z/0=0/0=0 - its impact to human beings through education and research