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meridian.backend.divide_no_nan Stay organized with collections
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Computes a safe divide which returns 0 if y
(denominator) is zero.
meridian
.
backend
.
divide_no_nan
(
x
,
y
,
name
=
None
)
For example:
>>>
tf
.
constant
(
3.0
)
/
0.0
< tf
.
Tensor
:
shape
=
(),
dtype
=
float32
,
numpy
=
inf
>
>>>
tf
.
math
.
divide_no_nan
(
3.0
,
0.0
)
< tf
.
Tensor
:
shape
=
(),
dtype
=
float32
,
numpy
=
0.0
>
Note that 0 is returned if y
is 0 even if x
is nonfinite:
>>>
tf
.
math
.
divide_no_nan
(
np
.
nan
,
0.0
)
< tf
.
Tensor
:
shape
=(),
dtype
=
float32
,
numpy
=
0.0
>
A Tensor
of a floating or integer dtype.
A Tensor
with the same dtype as x
and a compatible shape.
A name for the operation (optional).
The element-wise quotient as in tf.math.divide(x, y)
,
except that division by zero produces 0.0
, not nan
.
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, and code samples are licensed under the Apache 2.0 License
. For details, see the Google Developers Site Policies
. Java is a registered trademark of Oracle and/or its affiliates.
Last updated 2025-08-16 UTC.
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